Question

Find the sum of additive inverse and multiplicative inverse of 7.

Answer 1

The additive inverse of 7 = - 7
The multiplicative inverse of 7 $=\frac{1}{7}$
$\therefore$ Required sum $=-7+\frac{1}{7}=\frac{-49+1}{7}$
$=\frac{-48}{7}=-6\frac{6}{7}$