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Byju's Answer
Standard XII
Mathematics
Combination with Restrictions
Find the sum ...
Question
Find the sum of all
4
−
digit numbers that can be formed using the digit
1
,
3
,
5
,
7
,
9
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Solution
Total no. of digits are
5
, i.e.,
n
=
5
Total no. of digits required is
4
, i.e.,
r
=
4
Therefore,
No. of
4
digits no. that can be formed
=
n
P
r
=
5
P
4
=
5
!
1
!
=
120
No. of times each digit will appear
=
120
5
=
24
Sum of digits at unit place
=
24
(
1
+
3
+
5
+
7
+
9
)
=
24
×
25
=
600
Sum of all numbers
=
600
×
1000
+
600
×
100
+
600
×
10
+
600
=
666600
Hence the sum off all
4
diit numbers is
666600
.
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