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Question

Find the sum of all 4digit numbers that can be formed using the digit 1,3,5,7,9

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Solution

Total no. of digits are 5, i.e.,
n=5
Total no. of digits required is 4, i.e.,
r=4
Therefore,
No. of 4 digits no. that can be formed =nPr=5P4=5!1!=120
No. of times each digit will appear =1205=24
Sum of digits at unit place =24(1+3+5+7+9)=24×25=600
Sum of all numbers =600×1000+600×100+600×10+600=666600
Hence the sum off all 4 diit numbers is 666600.

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