Find the sum of all integers between 50 and 500, which are divisible by 7.
First number divisible by 7 in between 50 - 500 is 56
Last number divisible by 7 in between 50 - 500 is 497
Last term = 497 , first term = 56 , difference = 7 , so
497 = 56 + (n - 1)*d
497 - 56 = (n-1)*7
441 / 7 = (n - 1)
63 = n - 1
n = 64
So , there are 64 terms divisible in between 50 - 500 by 7
Now, applying the formula for additon
a = first term , l = last term
Sum = n / 2 [ a + l ]
= 64 / 2 [ 56 + 497 ]
= 17696
Ans: 17696