Find the sum of all integers between 84 and 719, which are multiple of 5.

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Solution

The required series is 85, 90, 95, ... , 715
Let there be n terms in the A.P.
We have, a = 85, d = 5
Then,
nth term = 715
715 = 85 + (n - 1)5
n = 127
Then,
$S_{n} = \frac{n}{2} [a + l] S_{127} = \frac{127}{2} [85 + 715] = 50800$

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Find the sum of all integers between 84 and 719, which are multiple of 5.

The required series is 85, 90, 95, ... , 715 Let there be n terms in the A.P. We have, a = 85, d = 5 Then, nth term = 715 715 = 85 + (n - 1)5 n = 127 Then, Sn=n2[a+l]S127=1272[85+715]=50800

The required series is 85, 90, 95, ... , 715
Let there be n terms in the A.P.
We have, a = 85, d = 5
Then,
nth term = 715
715 = 85 + (n - 1)5
n = 127
Then,
$S_{n} = \frac{n}{2} [a + l] S_{127} = \frac{127}{2} [85 + 715] = 50800$