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Question

# Find the sum of all natural numbers between 1 and 100, which are divisible by 3.

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Solution

## In this problem, we need to find the sum of all the multiples of 3 lying between 1 and 100. So, we know that the first multiple of 3 after 1 is 3 and the last multiple of 3 before 100 is 99. Also, all these terms will form an A.P. with the common difference of 3. So here, First term (a) = 3 Last term (l) = 99 Common difference (d) = 3 So, here the first step is to find the total number of terms. Let us take the number of terms as n. Now, as we know, So, for the last term, Further simplifying, Now, using the formula for the sum of n terms, We get, On further simplification, we get, Therefore, the sum of all the multiples of 3 lying between 1 and 100 is

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