Find the sum of all natural numbers between 200 and 1502 which are exactly divisible by 3.
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Solution
ap is 201, 204,........1500 a = 201 d = 3 an = 1500 an = a + (n-1)d 1500 = 201 + (n-1)3 1299 = (n-1)3 433 = n - 1 therefore, n =434 Sn=n/2x(a first+a last) =434/2x(201+1502) =217x1701 =369117