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Question

Find the sum of all natural numbers lying between 100 and 1000, which are multiples of 5

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Solution

Multiples of 5 are 5,10,15,.....
between 100 & 1000 are 105,1,0,.,995
a=105
d=5
l=995
an=a+(n1)d
995=105+(n1)5
995=100±5(n1)
895=5n
n=179
Sn=n2[2a+(n1)d]
=1792[2×105+(1791)×5]
=179×550
=98450
Sum is 98450.

1206477_1319954_ans_3049eddf374e43b08c4b7e3af780ccdb.jpg

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