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Byju's Answer
Standard VIII
Mathematics
Numbers in General Form
Find the sum ...
Question
Find the sum of all natural numbers that are less then
100
and divisible by
4
.
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Solution
The given series will be:
4
+
18
+
12
+
.
.
.
.
.
.
.
+
96
Or
4
(
1
+
2
+
3
+
.
.
.
.
.
.
.
+
24
)
The series is an
A
P
. So, using the formula for sum of n terms of an Arithmetic progression to find the required sum:
S
n
=
n
2
(
a
+
a
n
)
,
where
a
is the first term,
a
=
1
Common difference,
d
=
1
Number of terms,
n
=
24
1
+
2
+
3
+
⋯
+
24
=
n
(
n
+
1
)
2
=
24
×
25
2
=
12
×
25
=
300
Required Sum
=
4
(
300
)
=
1200
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