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Question

Find the sum of all natural numbers that are less then 100 and divisible by 4.

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Solution

The given series will be:
4+18+12+.......+96
Or 4(1+2+3+.......+24)
The series is an AP. So, using the formula for sum of n terms of an Arithmetic progression to find the required sum:
Sn=n2(a+an) ,
where a is the first term, a=1
Common difference, d=1
Number of terms, n=24
1+2+3++24=n(n+1)2=24×252=12×25=300
Required Sum=4(300)=1200

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