The numbers lying between 200 and 400 which are divisible by 7 are 203,210,217,...399
∴
First term, a=203
Last term, an=399 & Common
difference, d=7
Let the number of terms
of the A.P. be n.
∴an=399=a+(n−1)d⇒399=203+(n−1)7⇒7(n−1)=196⇒n−1=28⇒n=29∴S29=292(203+399)=292(602)=(29)(301)=8729
Thus,
the required sum is 8729