Question

Find the sum of all odd integers between 1 and 1000

Answer 1

Dear student,
required series: 3,5,7..........,999
A1=3
An=999
d=2
An=A1+(n-1)d
​​​​​999=3+(n-1)2
996=(n-1)2
498=n-1
n= 499
Sn=(n/2)(A1+An)
=(499/2)(3+999)
= (499×1002)/2
= 499×501
=249999
Regards