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Question

Find the sum of all odd integers between 2 and 100 divisible by 3.

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Solution

Such integers are 3,9,15,21,...99
This is an A.P with a=3
d=6
an=l=99
an=a+(n1)d
99=3+(n1)6
n=17
§n=n2(a+l)
S17=172(3+99)=867.

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