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Question

Find the sum of all odd natural numbers less than 200.

A
1000
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B
10100
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C
9900
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D
10000
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Solution

The correct option is D 10000
The odd natural numbers less than 200 are 1, 3, 5. . . 199

The numbers form an AP

Where, first term a=1
and common difference d=2
and last term an=199

We know that nth term of an AP =a+(n1)d

199=1+(n1)×2

1982=n1

n=99+1

n=100

We know
Sum of n terms of an AP =n2(2a+(n1)d)

Let the sum of odd natural numbers less than 200 be S100

S100=1002[1+199]

S100=50×200

=10000

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