All odd numbers between 100 and 200 are
101,103,105,......199
which forms an A.P
first term of this A.P is a1=101
second term of this A.P is a2=103
last term of this A.P is an=199
common difference
d=a2−a1
⟹d=103−101=2 .
nth term of this A.P is given by
an=a1+(n−1)d
put an=199;a1=101and d=2 in above equation we get,
⟹199=101+(n−1)2
⟹2n−2+101=199
⟹2n=199−99=100
n=1002=50 number of terms in this A.P
now, sum of these n=50 terms is given by
Sn=n2(a1+an)
put values of n=50;a1=101;an=199 we get
S50=502(101+199)
⟹S50=502×300
⟹S50=25×300
⟹S50=7500
hence the sum of all odd numbers between 100 and 200, is S50=7500