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Question

Find the sum of all the angles at the five vertices of the adjoining star.

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Solution

The given figure of a star is shown below.

To Find: A + B + C + D + E

In triangle BEP, B + D = QPD [Exterior angle property of triangles] … (1)

In triangle ACQ, A + C = PQD [Exterior angle property of triangles] … (2)

Now, in triangle PQD, QPD + PQD + D = 180° [Angle sum property of triangles]

⇒ (B + E) + (A + C) + D = 180° [Using (1) and (2)]

∴ ∠A + B + C + D + E = 180°


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