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Find the sum ...

Question

Find the sum of all the digits in the units place of all numbers formed with the help of $3, 4, 5, 6$ taken all at a time.

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Solution

Sum of the digits in the unit place
$= (4 - 1)! (3 + 4 + 5 + 6)$
$= 6 \times 18 = 108$

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