Question

Find the sum of all the three digit numbers divisible by 5.

• A. 99550
• B. 97560
• C. 98550
• D. 96000

Answer 1

The correct option is C 98550

The first 3 digit number divisible by 5 is 100.

The last 3 digit number divisible by 5 is 995.

Other numbers in between 100$\&$995 are 105, 110, 115... 990, 995: they form an AP with common difference 5.

Number of terms in the AP$=\left[\frac{(995-100)}{5}\right]+1=180$

So, sum of all the digits$=\left(\frac{180}{2}\right)[100+995]=98550.$