Question

Find the sum of (d)$-50,-200$ and $300$.

Answer 1

We have three integers, two negative integers and one positive integer.

First add two negative integers: $(-50-200)+300=-250+300$

To add two integers with opposite signs first ignore the signs, subtract the smaller integer from bigger integer and put the sign of bigger number.

$-250+300=+50$

Hence, the sum of $-50,-200$ and $300$. is $50.$