Find the sum of each arithmetic series (i) 38+35+32+.....+2 (ii) 6+514+412+....25terms
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Solution
(i) The given arithmetic series is 38+35+32+....+2 where the first term is a1=38, second term is a2=35 and the nth term is Tn=2.
We find the common difference d by subtracting the first term from the second term as shown below:
d=a2−a1=35−38=−3
We know that the general term of an arithmetic progression with first term a and common difference d is Tn=a+(n−1)d, therefore, with a=38,d=−3 and Tn=2, we have