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B
1+3+5+7+9+11+13+16+17+19=101
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C
1+3+5+7+10+11+13+15+17+19=101
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D
1+3+6+6+9+11+13+15+17+19=100
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Solution
The correct option is A1+3+5+7+9+11+13+15+17+19=100 The sum of first 10 consecutive odd numbers is 1+3+5+7+9+11+13+15+17+19 Since, we know the formula for sum of consecutive odd numbers = n2 So, n=10, Sum =(10)2=100