Find the sum of first 10 natural numbers.
Finding the sum:
The sum of the first 10 natural numbers is given by the formula:
Sn=n(n+1)2
Here n=10
⇒S=10(10+1)2⇒S=10×112⇒S=5×11⇒S=55
Hence, the sum of the first 10 natural numbers is 55.
Question 87
The sum of squares of first n natural numbers is given by 16n(n+1)(2n+1) or 16(2n3+3n2+n). Find the sum of squares of the first 10 natural numbers.