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Question

Find the sum of first 10 terms of the G.P 3, 6, 12, 24___

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Solution

a = 3

r = 2

Sum of n terms Sn = a(rn1)r1

S10 = a(r101)r1

= 3(2101)21

= (1024 - 1) × 3

=1023×3

= 3069


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