The below workout with step by step calculation shows how to find what is the sum of natural numbers or positive integers from 1 to 1000 by applying arithmetic progression. It's one of an easiest methods to quickly find the sum of any given number series.
step 1
address the formula input parameters & values.
Input parameters & values:
The number series 1, 2, 3, 4, . . . . , 999, 1000.
The first term a = 1
The common difference d = 1
Total number of terms n = 1000
step 2
apply the input parameter values in the formula
Sum = n/2 x (a + Tn)
= 1000/2 x (1 + 1000)
= 1001000/2
1 + 2 + 3 + 4 + . . . . + 999 + 1000 = 500500
Therefore, 500500 is the sum of positive integers upto 1000