Find the sum of first $24$ terms of an AP whose $n^{t h}$ term is given by $a_{n} = 3 + 2 n$ .

568

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624

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564

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672

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Solution

The correct option is D
672

Given,
$a_{n} = 3 + 2 n$
So, First term = $a_{1} = 3 + 2 \times 1 = 5$
Last term = $a_{24} = 3 + 2 \times 24 = 51$

We know, sum of n terms is given by
$S_{n} = \frac{n}{2} (a + l)$

To find $S_{24}$ , we have $n = 24, a_{1} = 5, a_{24} = 51$

$∴ S_{24} = \frac{24}{2} (5 + 51)$

$= 12 (56) = 672$

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Similar questions

Find the sum of the first $24$ terms of an AP whose $n^{th}$ term is given by $t_{n} = 3 + 2 n .$

Find the sum of first $24$ terms of the A.P. whose $n^{t h}$ term is given by $a_{n} = 3 + 2 n$

To find the sum of the first 24 terms of an AP whose $n^{t h}$ term is given by $a_{n} = 3 + 2 n$ , what is the best approach to solve this question?

15

3 - 2 n

31

n^{t h}

(3 + \frac{2 n}{3})

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