Question

Find the sum of first 49 even natural numbers.

• A. 2450
• B. 2550
• C. 2350
• D. 2650

Answer 1

The correct option is A

2450

The first even natural number is 2.
The given sequence forms an A.P. with first term as 2 and common difference as 2.
Number of terms =49
Sum of the first 49 natural even numbers = $n\frac{(2x+(n-1\left)d\right)}{2}$
$=49\frac{(2\times 2+(49-1\left)2\right)}{2}$
= 2450.