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Question

Find the sum of first n natural numbers.

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Solution

We know first n natural numbers are
1,2,3.......n
let S=1+2+3+......+n
write in reverse order we get
S=n+n1+n2+.....+1
2S=(n+1)+(n+1)+........+(n+1)n times
2S=n(n+1)
S=n(n+1)2.

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