Question

Find the sum of
(i) 137 and −354
(ii) 1001 and −13
(iii) −3057 and 199
(iv) −36 and 1027
(v) −389 and −1032
(vi) −36 and 100
(vii) 3002 and −888
(viii) −18, + 25 and −37
(ix) −312, 37 and 192
(x) −51, −203, 36 and −28

Answer 1

$\begin{array}{l}\left(\text{i}\right)\text{137 and}-\text{354}\\ -\text{354}\\ \frac{+137}{-217}\\ \\ \left(\text{ii}\right)\text{1}00\text{1 and}-\text{13}\\ 1001\\ \frac{-13}{988}\\ \\ \text{(iii)}-\text{3}0\text{57 and 199}\\ -\text{3}0\text{57}\\ \frac{\text{199}}{-2858}\\ \\ \left(\text{iv}\right)-\text{36 and 1}0\text{27}\\ \text{3}0\text{57}\\ \frac{-\text{36}}{3021}\\ \\ \left(\text{v}\right)-\text{389 and}-\text{1}0\text{32}\\ -\text{1}0\text{32}\\ \frac{-\text{389}}{-1421}\\ \\ \left(\text{vi}\right)-\text{36 and 1}00\\ \text{1}0\text{0}\\ \frac{-\text{36}}{64}\\ \\ \text{(vii) 3}00\text{2 and}-\text{888}\\ \text{3}00\text{2}\\ \frac{-\text{888}}{2114}\end{array}$
(viii) −18, + 25 and −37
25 + (−18) + (−37)
= 25 – (18 + 37)
= 25 – 55
= –30

(ix) −312, 39 and 192
39 + 192 + (−312)
= 39 + 192 - 312
= 231 −312
= −81
(x) −51, −203, 36 and −28
36 + (−51) + (−203) + (−28)
= 36 − (51 + 203 + 28)
= 36 – 282
= −246