Find the sum of :
(i) all odd natural numbers less than 50.
(ii) first 12 natural numbers each of which is a multiple of 7.
(i) For odd numbers a=1d=2
last term (less than 50) = 49
an=a+(n−1)d1+(n−1)2=49(n−1)2=48n−1=24n=25
Sum of n terms, Sn=n2[a+l]S25=252[1+49]=252×50=625
(ii) For multiples of 7 a=7d=7n=12
Sum of n terms, Sn=n2[2a+(n−1)d]S12=122[2(7)+11×7]=6×[14+77]=6×91=546