Question

Find the sum of:
(ii) 3𝑎+5𝑏+2𝑐, 2𝑎+3𝑏−𝑐 and 𝑎+𝑏+𝑐

Answer 1

Step: Find the sum of given expressions (3𝑎+5𝑏+2𝑐), (2𝑎+3𝑏−𝑐) and (𝑎+𝑏+𝑐)
We need to add (3𝑎+5𝑏+2𝑐), (2𝑎+3𝑏−𝑐) and (𝑎+𝑏+𝑐) = (3𝑎+5𝑏+2𝑐)+(2𝑎+3𝑏−𝑐)+(𝑎+𝑏+𝑐)
= (3𝑎+2𝑎+𝑎)+(5𝑏+3𝑏+𝑏)+(2𝑐+𝑐−𝑐) [Grouping like terms]
=(5𝑎+𝑎)+(8𝑏+𝑏)+(2𝑐)
=6𝑎+9𝑏+2𝑐
Hence, the answer is 𝟔𝒂+𝟗𝒃+𝟐𝒄.