Find the sum of interior angles of a parallelogram.

180^o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

360^o

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

540^o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

240^o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
360^o

Sum of interior angle = (n-2) $\times$ 180 $^{\circ}$

Where n is the number of sides in a polygon

Parallelogram has 4 sides, so n = 4

Sum of interior angle = (2) $\times$ 180 $^{\circ}$ = 360 $^{\circ}$

Suggest Corrections

Similar questions

Q. Sum of all interior angles of a parallelogram is :

We know that the sum of the interior angles of a triangle is $180^{\circ}$ . Show that the sums of the interior angles of polygons with 3, 4, 5, 6, …. sides form an arithmetic progression. Find the sum of the interior angles for a 21 sided polygon.

Q. We know that the sum of the interior angles of a triangle is 180°. Show that the sums of the interior angles of polygons with 3, 4, 5, 6, ... sides form an arithmetic progression. Find the sum of the interior angles for a 21 sided polygon. [NCERT EXEMPLAR]

Q. The bisectors of interior angles of a parallelogram forms a ___________.

Q. Find the sum of interior angles of a polygon with

8

sides.

Join BYJU'S Learning Program

Find the sum of interior angles of a parallelogram.

The correct option is B 360o Sum of interior angle = (n-2) × 180∘ Where n is the number of sides in a polygon Parallelogram has 4 sides, so n = 4 Sum of interior angle = (2) × 180∘ = 360∘

The correct option is B
360^o

Sum of interior angle = (n-2) $\times$ 180 $^{\circ}$

Where n is the number of sides in a polygon

Parallelogram has 4 sides, so n = 4

Sum of interior angle = (2) $\times$ 180 $^{\circ}$ = 360 $^{\circ}$