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Question

find the sum of measures of all interior angles of a polygon with number of sides 8

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Solution

Dear student,
$T h e s u m o f t h e i n t e r i o r a n g l e s, i n d e g r e e s, o f a r e g u l a r p o l y g o n i s g i v e n b y t h e f o r m u l a = 180 (n - 2), - - [w h e r e n i s t h e n u m b e r o f s i d e s] h e r e n = 8 = 180 (8 - 2) = 180 \times 6 = 1080$
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