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Question

Find the sum of n terms of the series 1.5+2.15+3.31+4.53+5.81+....

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Solution

5153153quad81....
10162228....
666....
un=5+10(n1)+3(n1)(n2)
=5+10n10+3n29n+6
=3n2+n+1
tn=n(3n2+n+1)
=3n3+n2+n
Sn=tn=3n2(n+1)24+n(n+1)(2n+1)6+n(n+1)2
=n(n+1)12(9n2+13n+8)

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