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Question

Find the sum of n terms of the series 3.4+8.11+15.20+24.31+35.44+....

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Solution

38152435....
57911....
222....
un=n2+2n
411203144....
791113....
222....
un=n2+4n1
tn=(n2+2n)(n2+4n1)
=n(n+2)((n+1)(n+3)4)
=n(n+1)(n+2)(n+3)4n(n+2)
Sn=n(n+1)(n+2)(n+3)(n+4)54n(n+1)(n+2)32n(n+1)
=n(n+1)15(3n2+27n2+58n+2)

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