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Question

Find the sum of n terms of the series 12.4+1.32.4.6+1.3.52.4.6.8+1.3.5.72.4.6.8.10+....

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Solution

tn=135(2n1)246(2n+2)
tn=135(2n1)2462n135(2n+1)246(2n+2)
tn1=135(2n3)246(2n2)135(2n1)2462n
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t1=121234
Sn=12135(2n+1)246(2n+2)

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