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Question

Find the sum of n terms of the series loga+loga2b+loga3b2+loga4b3+__________ to n terms.

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Solution

TnTn1=loganbn1logan1bn2
=loganbn1bn2an1=logab=constant as it is independent of n. Hence the given series is an A.P. whose A=loga and D=logab.
S=n2[2loga+(n1)logab]
=n2[nlogab+2loga(logalogb)]
=n2[nlogab+logab].

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