Find the sum of $n$ terms of the series whose $n t h$ term is :
$n^{2} + 2^{n}$

Open in App

Solution

$\sum n^{2} + 2^{n}$
$\sum n^{2} + \sum 2^{n}$
$\frac{n (n + 1) (2 n + 1)}{6} + \frac{1 (2 (2^{n}) - 1)}{2 - 1}$
$\frac{n (n + 1) (2 n + 1)}{6} + \frac{2 (2^{n}) - 1}{1}$

Suggest Corrections

Similar questions

Find the sum to n terms of the series whose nth term is given by

$n^{2} + 2^{n}$

n

n t h

(2 n - 1)^{2}

n

n^{t h}

\frac{n^{3} + 3 n^{2} + 2 n + 2}{n^{2} + 2 n}

n

n^{t h}

n^{3} + \frac{3}{2} n

Find the sum to n terms of the series whose n^th terms is given by n² + 2ⁿ

Join BYJU'S Learning Program