Question

Find the sum of numbers Between 250 and 500 That are divisible by 5

Answer 1

The first number is $250$

The common difference is $5$

The last number is $500$

$l=a+(n-1)d500=250+5n-55n-5=2505n=255n=51Sum=\frac{51}{2}\left[2\right(250)+(50\left)\right)5\left]\frac{51}{2}\right(500+250)=51\times 375=19125$