CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Find the sum of odd interges from  1 to 2001 , 


Solution

All odd intergers from 1 to 1000 are 1, 3, 5, 7,   ........... 2001,

Here a = 1, d = 3 - 1  = 2,  an = 2001.

We have that  an=a+(n1)d

          2001 = 1+(n1)×2

20011=(n1)×220002=n1

n=1000+1=1001

Now,   sn=n2[a+1]

s1001=10012[1+2001]=10012×2002

= 1002001[l=an=2001]

flag
 Suggest corrections
thumbs-up
 
0 Upvotes



footer-image