The correct option is A 2025
The sum of first n terms of arithmetic series formula can be written as,
Sn=n2[2a+(n−1)d] ............ (1)
The list of odd numbers between 0 and 90 is 1,3,5,7,9,..........89
Where n= number of terms
a= first odd number ⇒ 1
d= common difference of A.P. ⇒2
Tn= Last term ⇒ 89
Tn=a+(n−1)d
89=1+(n−1)2
89=1+2n−2
89−1+2=2n
90=2n
n=45
Apply the given data in the formula (1),
S45=452[2×1+(45−1)2]
=22.5[2+(44)2]
=22.5[2+88]
=22.5[90]
=2025
So, the sum of odd numbers between 0 and 90 is 2,025.