Find the sum of oxidation state of phosphorus in $H_{3} P O_{4}$ and $H_{3} P O_{3}$ .

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Solution

Oxidation state of P in $H_{3} P O_{4}$ is 5 and oxidation state of P in $H_{3} P O_{3}$ is 3 ( taking oxidation state of oxygen is -2 and hydrogen +1). So sum is $5 + 3 = 8$ .

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