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Byju's Answer
Standard XII
Mathematics
Summation by Sigma Method
Find the sum ...
Question
Find the sum of series
1
+
(
2
)
(
3
)
+
(
4
)
+
(
5
)
(
6
)
+
7
+
.
.
.
.
upto
50
term.
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Solution
Sum of
1
+
(
2
)
(
3
)
+
4
+
(
5
)
(
6
)
+
7
−
−
−
−
−
−
up to 50 terms.
1
+
4
+
7
+
10
+
13
−
−
−
−
−
−
−
−
−
+
73
+
(
2
)
(
3
)
+
(
5
)
(
6
)
+
(
8
)
(
9
)
−
−
−
−
−
⇒
1
+
4
+
7
+
10
+
13
−
−
−
−
+
73
=
73
=
1
+
(
n
−
1
)
3
=
73
=
1
+
3
n
−
3
=
72
+
3
=
3
n
n
=
25
=
25
2
(
2
+
(
24
)
3
)
=
25
2
(
2
+
72
)
=
25
×
37
=
925
⇒
(
2
)
(
3
)
+
(
5
)
(
6
)
+
(
8
)
(
9
)
−
−
−
−
+
(
74
)
(
75
)
⇒
n
=
1
∑
25
(
3
n
−
1
)
(
3
n
)
⇒
3
2
n
−
3
n
n
=
1
∑
25
9
n
−
3
n
n
=
1
∑
25
9
n
−
n
=
1
∑
25
3
n
⇒
9
26
+
4
(
3
26
)
−
12
8
+
925
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0
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Q.
Let
S
50
=
1
+
(
2
)
(
3
)
+
4
+
(
5
)
(
6
)
+
7
+
(
8
)
(
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)
+
.
.
.
upto
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...
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