Find the sum of series upto 10 terms
$2, 5, 8, 11, . . .$

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Solution

The given series is $2, 5, 8, 11, . . .$ form AP
With $a = 2, d = 3$
Sum of $10$ terms is $\frac{10}{2} [2 (2) + (10 - 1) 3] 5 (4 + 27) = 153$

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