Find the sum of solutions of equation (5+2√6)x2−3+(5−2√6)x2−3=10.
A
0
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B
2√2
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C
−2√2
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D
2
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Solution
The correct option is A0 Substitute t=(5+2√6)x2−3 Hence, 1t=(5−2√6)x2−3 ⇒t+1t=10 ⇒t=5±2√6 Hence, x2−3=±1 Hence, x=2,−2,√2,−√2 Hence, the sum of the roots is 0