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Question

Find the sum of terms of the sequence till n terms : 6+9+16+27+42+....+n terms.

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Solution

S=6+9+16+27+42+.......n terms
S=6+9+16+27+.............
O=6+(3+7+11+15+...n+ terms)- Tn
Tn=6+n12(2.3+(n2)4)
Tn=6+(n1)(4n22
Tn=6+(n1)(2n1)
Tn=2n23n+7
Snr=1Tr=2nr=1r2+7nr=113nr=1r
=2(n)(n+1)(2n+1)6+7n3n(n+1)2
=2n(n+1)(2n+1)+42n9n(n+1)6
=4n3+2n2+4n2+2n+42n9n29n6
=4n23n2+35n6





















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