Question

Find the sum of the ${14}^{th},{16}^{th},and{18}^{th}$ multiple of $7$

Answer 1

The ${14}^{th},{16}^{th},and{18}^{th}$ multiple of $7$ are,
$7\times 14=98$
$7\times 16=112$
$7\times 18=126$
Therefore the required sum = 98 + 112 + 126 = 336