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Index of (r+1)th Term from End When Counted from Beginning

Find the sum ...

Question

Find the sum of the coefficients of the terms of the expansion $(1 + x + 2 x^{2})^{6}$ .

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Solution

Substituting $x = 1$ , we have $(1 + 1 + 2)^{6}$ , which gives us the sum of the coefficients of the terms of the expansion.
Therefore, sum = $4^{6}$

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