Find the sum of the coefficients when given equation is balanced.
$A l_{2} (S O_{4})_{3} + C a (O H)_{2} \to A l (O H)_{3} + C a S O_{4}$

5

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6

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7

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8

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9

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Solution

The correct option is E $9$
The unbalanced chemical equation is:
$A l_{2} (S O_{4})_{3} + C a (O H)_{2} \to A l (O H)_{3} + C a S O_{4}$
Balance $A l$ atoms by multiplying $A l (O H)_{3}$ with 2.
$A l_{2} (S O_{4})_{3} + C a (O H)_{2} \to 2 A l (O H)_{3} + C a S O_{4}$
Balance $S$ atoms by multiplying $C a S O_{4}$ with 3.
$A l_{2} (S O_{4})_{3} + C a (O H)_{2} \to 2 A l (O H)_{3} + 3 C a S O_{4}$
Balance $C a$ atoms by multiplying $C a (O H) - 2$ with 3.
$A l_{2} (S O_{4})_{3} + 3 C a (O H)_{2} \to 2 A l (O H)_{3} + 3 C a S O_{4}$
This is the balanced chemical equation. The sum of the coefficients is $1 + 3 + 2 + 3 = 9$

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