First 15 positive odd numbers will be,
1,3,5,7,9,…
We can observe that these numbers are in A.P.
The sum of first n terms of an A.P whose first term is a and common difference is d can be written as, Sn=n2[2a+(n−1)d].
From the series of first positive odd numbers we can conclude that, a=1 and d=2.
Substitute the values of a, d and n in the formula of sum of first n terms of an A.P,
S15=152[2×1+(15−1)2]=7.5[2+14×2]=7.5[2+28]=7.5[30]=225
So, the sum of the first 15 positive odd numbers of the A.P. is 225.