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Question

Find the sum of the first 15 terms of each of the following sequences having nth term as
(i) an=3+4n (ii) bn=5+2n (iii) xn=6n (iv) yn=95n

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Solution


Sum of 15 terms: No. of terms x (first term + last term)/2
1.

an=3+4n
a1=3+4=7
l=3+4 x 15=63

Sum of 15 terms: No. of terms x (first term + last term)/2
=15(7+63)/2
=525
2.
bn =5+2n
b1=7
l=35
Sum of 15 terms : No. of terms x (first term + last term)/2
=15(35+7)/2
=315
3.
xn=6-n
x1=6-1=5
l=6-15=-9
Sum of 15 terms : No. of terms x (first term + last term)/2
=15(5 - 9)/2
=-30
4.
yn=9-5n
y1=9-5=4
l=9-75=-66
Sum of 15 terms : No. of terms x (first term + last term)/2
= 15(4-66)/2
=-15 x 31
=-465


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