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Question

Find the sum of the first 15 terms of the following sequence having nth term as
an=3+4n

A
525
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B
563
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C
184
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D
189
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Solution

The correct option is A 525
an=3+4n (Given)
Now,
a1=3+4×1=7
a2=3+4×2=11
a3=3+4×3=15
So the series is
The sum of first is turns is
Sn=n2[2a+(n1)d]
a=7,n=15,d=4
Sn=152[2×7+(151).4]
Sn=152[14+56]
Sn=15×702
Sn=15×35
Sn=525
The sum of first 15 terms of given series is
Sn=525

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