Find the sum of the first n natural numbers.
First n natural numbers 1,2,3,4,5,6,.................... n terms
Sn = 1+2+3+4+5+6+..........(n-2) + (n-1) + n ------------(1)
We can also write above given series in reverse order
Sn = n + (n-1) + (n-2) +...............4,3,2,1 ----------------(2)
we find sum of first and last term = sum of second and second last term so,on.....
Equation 1 + Equation 2
2Sn = (n+1) + (n+1) + (n+1) ......... n times
2Sn =n.(n+1)
Sn = n(n+1)2